Mathematics 1 Deneme Sınavı Sorusu #1232003

5657

3568

2563

1896

567

Yanıt Açıklaması:

Given the initial bacteria population Q(0), the population at time t is given by Q(t)=Q(0)e^kt.

Since we know that population doubles in 4 hours, we can write:

2Q(0)=Q(0)e^4k

2=e^4k

ln2=4k, so k=ln2/4=0.1733

Then Q(t=10)=1000e^10k

=1000.e^1.733

=5657 (approximately)

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