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Mathematics 1
Mathematics 1 Deneme Sınavı
Mathematics 1 Deneme Sınavı Sorusu #1231826
Mathematics 1 Deneme Sınavı Sorusu #1231826
If the half-life of a radioactive material is 3000 years, how much of the 100 grams will remain after 5000 years?
15.6 |
22.7 |
26.8 |
28.6 |
31.5 |
Yanıt Açıklaması:
The quantity at time t is given by the formula Q(t)=Q(0)*ekt where Q(0) is the initial amount.
Since the half life is 3000 years, we can write:
0.5Q(0)=Q(0)*e3000k which means that:
0.5=e3000k
ln0.5=lne3000k
ln0.5=3000k
ln0.5/3000=k
Thus, after finding k we can calculate:
Q(t=5000)=100*e5000*ln0.5/3000
=100*e5*ln0.5/3
=100*e-1.155=31.49
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