Statıstıcs I Deneme Sınavı Sorusu #821637

What must be the value of "a" if the table above is the probability distribution of variable X whose mean is 2.8?


0.1

0.2

0.3

0.4

0.5


Yanıt Açıklaması:

If this is a probabilty distribution than the sum of all probabilities must be equal to 1. Thus 0.2+0.3+0.1+a+b=1 which means a+b=0.4, thus b=0.4-a. Also it is given that the mean of X is equal to 2.8.

Mean=Sum((X=x)P(X=x))

2.8=(1*0.2)+(2*0.3)+(3*0.1)+(4*a)+(5*b)

2.8=1.1+4a+5b

1.7=4a+5b=4a+5(0.4-a)

1.7=2-a

0.3=a

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