Note that there are five different letters, namely U, S, A, L, Y and that the letters U and L are used twice. If all the seven letters in the given word were different, the total number of arrangements would be 7!. Since all the arrangements of the two letters U1 and U2 , and all the arrangements of the two letters L1 and L2 should be counted only once, it follows that the answer is 7!/ 2!2! =15. The correct answer is C.