Statıstıcs I Deneme Sınavı Sorusu #822031
A call center receives, on average, 6 calls per minute and number of calls follows a Poisson distribution. What is the probability of receiving at most 2 calls at a given minute?
|
0.062 |
|
0.044 |
|
0.028 |
|
0.014 |
|
0.006 |
Yanıt Açıklaması:
We have to compute P(x=0)+P(x=1)+P(x=2) in order to find the probability of at most 2 calls at a given minute.
P(x=0)=(e-6*60)/0!=0.00248
P(x=1)=(e-6*61)/1!=0.0149
P(x=2)=(e-6*62)/2!=0.0446
Thus P(x=0)+P(x=1)+P(x=2)=0.06198
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