Statıstıcs I Deneme Sınavı Sorusu #821446

What is the variance of the probability distribution given above?


3.62

3.20

3

2.24

1.68


Yanıt Açıklaması:

We have to first compute the mean of the distribution in order to calculate the variance.

Mean=Sum(X.P(X=x))=(1*0.1)+(2*0.2)+(3*0.1)+(4*0.3)+(5*0.2)+(6*0.1)

=0.1+0.4+0.3+1.2+1+0.6=3.6

Variance=Sum(P(X)*(X-Mean)2)=0.1*(1-3.6)2+0.2*(2-3.6)2+0.1*(3-3.6)2+0.3*(4-3.6)2+0.2*(5-3.6)2+0.1*(6-3.6)2=2.24

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