vertex = (h, k) ; h =- b / 2a for y = a x² + b x + c ; k = 9 – 18 + 4 = -5 . pg. 60. Correct answer is C.

 A={2, 4, 6, 7}, B={1, 2, 3, 4} and C={8, 7,4}. AUB={1,2,3,4,6,7} and AUBUC={1,2,3,4,6,7,8}. The answer is B.

x²-5x+6=(x-2)(x-3)=0

So either x-2=0 or x-3=0 could satisfy this equation.

If x-2=0, then x=2

and if x-3=0, then x=3.

Thus the solution set is (2,3)

x = 3^1/2 = 1.732.... . Correct answer is E.

A ∪ B = {1, 2, 3, 4, 5}, A ∩ B = {3},
A \ B = {1, 2}, B \ A = {4,5},
A^c = {5, 6, 7, 8, 9, 10}, B^c = {1, 2, 6, 7, 8, 9, 10}.

By using the graph which is given in the question;

f(-5)=1, f(-4)=8, f(3)=-6 and f(5)=6 then,

f(-4)+3f(5)-2f(3)=8+(3.6)-(2.-6)=8+18-(-12)=38

f(x)=2x+7 and g(x)=3x-2 ›(gof)(x)=3.(2x+7)-2=6x+21-2=6x-19

f(x)=3x-8 › f(3)=3.3-8=1

g(x)=(x+12)/4 › g(8)=(8+12)/4=20/4=5

f(3).g(8)=1.5=5

c = log₂ (5 / 10) = log₂ 2^-1 ; log₂ c = 2^-1 ; 3 = 9^1/2 ; x = 2^-1 1/2 = 2^-2 = 0.25 . Correct answer is A.

x = 2 + 3 x³ – x + 1 = 1 . Correct answer is D.

Consider the function f: . 

For every x₁, x₂A if  x₁ ? x₂ implies

f(x₁) ? f(x₂)

then the function f is called one-to-one (or injective), so the correct answer is A.

Although the range and the image of a function are two concepts that need to be distinguished, we still know that they are closely related. The image is always a subset of the range. Yet, there are functions for which the range and the image sets are exactly the same. Thus, given a function f : if the image is equal to the range, i.e. f (A)=B the function f  is called surjective (onto). Equivalently, for every element b of the set B if there can be found an element a of A such that f (a)=b, then f  is called onto.

If a function which is both one-to-one and onto is called a bijection.

Constant function and identity function are the concepts related to types of functions.

A function assigning each element from its domain a single element in its range is called a constant function.

Given A ?, a function defined on the set A and assigning every element of A to itself is called the identity function.

Consider the function that assigns to each real number three times itself and four. If we denote this real number by x, and the function by f we may express it as

It is customary to also denote this function by y = f (x).

In the expression y = f (x), x is called the independent variable, whereas y is called the dependent variable.

In the expression y is called the dependent variable.

In the equation y = f (x)=3x+4, the dependent variable y is a function of the independent variable x.

As also understood from the information given, the correct answer is E. All of the statements in the options are correct.

3²=9 3^-2=1/9

So, (3²-3^-2)/(3²+3^-2)=(9-1/9)/(9+1/9)=(80/9)/(82/9)=80/82

(4f –2g)(x) = 4(x-2) - 2(2x-9) = 4x - 8 - 4x + 18 = 10

I. x with degree is 1.

II. 3x+ 1 with degree is 1.

III. 1 with degree is 0. Therefore the answer is A. 

Substituting 3 for x we find f (3) = 5.3 - 4 = 15 – 4 = 11, so the correct answer is A.