Mathematics 1 Deneme Sınavı Sorusu #1192933

log52 . log43 . log95=?


1/6

1/2

1

2

6


Yanıt Açıklaması:

using the change-of-base formula, log52=ln2/ln5

log43=ln3/ln4=ln3/ln2²=ln3/2ln2

log95=ln5/ln9=ln5/3ln3

then,log52 . log43 . log95=(ln2/ln5) . (ln3/2ln2) . (ln5/3ln3)=1/6

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