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Mathematics 1
Mathematics 1 Deneme Sınavı
Mathematics 1 Deneme Sınavı Sorusu #1357111
Mathematics 1 Deneme Sınavı Sorusu #1357111
At which (x,y) point is the value of the function y=f(x)=x2-6x+5 is minimum?
(0,5) |
(3,0) |
(6,1) |
(2,-3) |
(3,-4) |
Yanıt Açıklaması:
The first derivative must be equal to zero and the second derivative must be positive for a minimum value of a function. Thus:
f(x)=x2-6x+5
f'(x)=2x-6=0 so 2x=6, x=3 and when x=3 y=f(x)=9-18+5=-4
The second derivative is:
f''(x)=2>0
Thus for given function, point (3,-4) is the minimum.
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