Mathematics 1 Deneme Sınavı Sorusu #1357115

What is the equation for the tangent line to the function f(x)=x2-2x+1at point (2,1)?


y=x-1

y=2x-3

y=3x-5

y=x+1

y=x


Yanıt Açıklaması:

The equation of tangent line is given by the formula:

y – f(x0) = f'(x0)(x – x0)

x0=2 and f(x0)=1 are given.

Since f(x)=x2-2x+1 then f'(x)=2x-2 and f'(x0)=2*2-2=2 for x0=2.

Thus the equation for the tangent line will be:

y-1=2(x-2)

y-1=2x-4

y=2x-3

Yorumlar
  • 0 Yorum