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Mathematics 1
Mathematics 1 Deneme Sınavı
Mathematics 1 Deneme Sınavı Sorusu #1357115
Mathematics 1 Deneme Sınavı Sorusu #1357115
What is the equation for the tangent line to the function f(x)=x2-2x+1at point (2,1)?
y=x-1 |
y=2x-3 |
y=3x-5 |
y=x+1 |
y=x |
Yanıt Açıklaması:
The equation of tangent line is given by the formula:
y – f(x0) = f'(x0)(x – x0)
x0=2 and f(x0)=1 are given.
Since f(x)=x2-2x+1 then f'(x)=2x-2 and f'(x0)=2*2-2=2 for x0=2.
Thus the equation for the tangent line will be:
y-1=2(x-2)
y-1=2x-4
y=2x-3
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