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Mathematics 1
Mathematics 1 Deneme Sınavı
Mathematics 1 Deneme Sınavı Sorusu #1357096
Mathematics 1 Deneme Sınavı Sorusu #1357096
Let m=9 be the slope of the tangent line to the curve
y=(a+3) x3-2x2-5x at the point x=1. What is the value of a?
0 |
1 |
3 |
6 |
8 |
Yanıt Açıklaması:
The solution is quite straightforward. The slope is the derivative of the function at the given point so f' (x)=3(a+3) x2-4x-5 whose value at x=1 is m=3(a+3)-9. This value is 9 so that a=3.
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