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Mathematics 1
Mathematics 1 Deneme Sınavı
Mathematics 1 Deneme Sınavı Sorusu #1228696
Mathematics 1 Deneme Sınavı Sorusu #1228696
The private electric company EsLeki supplying electric to the citizens of Eskişehir has a monthly demand of p(x)=200-3x, where x corresponds to one kilowatt hour. The cost function of the company is given by C(x)=75+80x-x2, 0?x?40. What is the value of x ?
10 |
20 |
30 |
40 |
50 |
Yanıt Açıklaması:
The profit function we would like to maximise is P(x)=R(x)-C(x)
R(x)=x p(x)=x ·(200-3x)=200x -3x2
so that
P(x)=-2x 2 +120x-75
To find the maximum price, let us take the derivative of P(x) and equate it to zero:
P'(x)=-4x+120 = 0 ? x=30
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