Mathematics 1 Deneme Sınavı Sorusu #1233200

-y-2z/x

-z-2y/x

-x-2z/y

-x-2y

x+y

Yanıt Açıklaması:

x²y-3y²+2zx=0

2xydx+x²dy-6ydy+2xdz+2zdx=0

Since we are interested in dz/dx we can take dy=0 (y doesnt is constant).

So 2xydx+2xdz+2zdx=0 then 2xdz=-2xydx-2zdx and divind both sides to dx we obtain 2xdz/dx=-2xy-2z

so dz/dx=(-2xy-2z)/2x=-y-2z/x

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