Mathematics 2 Deneme Sınavı Sorusu #365025


(2x+4)e2x+c

2e2x+4x2+x+c

xe2x+c


Yanıt Açıklaması:

Let us use the integration by parts method. Let u=4x+10 which gives du=4dx. Also, let dv=e2xdx which gives

.

Substituting these values into ∫udv=uv-∫vdu  we get;

for any arbitrary real number c.

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