Statıstıcs I Deneme Sınavı Sorusu #836458
The probability that Navigator A shows wrong way to an address is 0.09 and the probability that Navigator B shows wrong way to the same address is 0.07 and the probability that both Navigators show wrong way to the same address is 0.04. What is the probability that only one of the Navigators shows wrong way to the same address?
|
0.16 |
|
0.14 |
|
0.12 |
|
0.10 |
|
0.08 |
Yanıt Açıklaması:
P(A) – P(A and B) + P(B) – P(A and B) = 0.09 – 0.04 + 0.07 – 0.04 = 0.08 . pg. 138. Correct answer is E.
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