Statıstıcs I Deneme Sınavı Sorusu #851028
For X which is a continuous random variable that is uniformly distributed and takes values between 3 and 9. What is the variance of the random variable X ?
12 |
14 |
16 |
18 |
20 |
Yanıt Açıklaması:
For X which is a continuous random variable that is uniformly distributed and takes values between 3 and 9, the minimum value of the random variable X is 3 (it’s the value of a) and the maximum value is 9 (it’s the value of b). Then X~U (a=3, b=9) and the probability density function of the continuous random variable X is defined as, f (x) = 1/(b - a) = 1/(9 - 3)= 1/6 for 3?x?9. The variance is equal to (9 - 3)2/2 = 18. The answer is D.
Yorumlar
- 0 Yorum