Statıstıcs I Deneme Sınavı Sorusu #851017
For X which is a continuous random variable that is uniformly distributed and takes values between 3 and 9. What is the probability density function of the random variable X ?
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f(x)=0 for 3≤x≤9 f(x)=1/6 otherwise |
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f(x)=1/6 for 3≤x≤9 f(x)=0 otherwise |
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f(x)=1/3 for 3≤x≤9 f(x)=0 otherwise |
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f(x)=1/2 for 3≤x≤9 f(x)=0 otherwise |
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f(x)=1/6 |
Yanıt Açıklaması:
For X which is a continuous random variable that is uniformly distributed and takes values between 3 and 9, the minimum value of the random variable X is 3 (it’s the value of a) and the maximum value is 9 (it’s the value of b). Then X~U (a=3, b=9) and the probability density function of the continuous random variable X is defined as, f (x) = 1/(b − a) = 1/(9 − 3)= 1/6 for 3≤x≤9. The answer is B.
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