Statıstıcs I Deneme Sınavı Sorusu #836451
A box contains 10 glasses : 4 red and 6 blue. Two glasses are selected randomly, without replacement, from this lot. What is the probability that the first selected glass is blue?
3 / 5 |
7 / 15 |
7 / 12 |
17 / 24 |
3 / 4 |
Yanıt Açıklaması:
S = {BR , BB , RB , RR} ; C(10, 2) = 10! / (2! * (10-2)!) = 10! / (2! * 8!) = 10 * 9 / 2 = 45 ; P(BR) + P(BB) = (6 / 10) * (4 / 9) + (6 / 10).* (5 / 9) = 6 * 4 / (10 * 9) + 6 * 5 / (10 * 9) = 4 / 15 + 1 / 3 = 9 / 15 = 3 / 5. pg. 137. Correct answer is A.
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